The Vividh Bharati station of All India Radio | vedclass

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Question

(A) The wavelength,$\lambda$,is calculated using the formula $\lambda = c / 
u$,where $c$ is the speed of light $(3.00 	imes 10^{8} \, m \, s^{-1})$

Vedclass · Accepted Answer

$219.3 \, m$,Radio waves

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(A) The wavelength,$\lambda$,is calculated using the formula $\lambda = c / 
u$,where $c$ is the speed of light $(3.00 	imes 10^{8} \, m \, s^{-1})$ and $
u$ is the frequency.Given frequency $
u = 1368 \, kHz = 1368 	imes 10^{3} \, s^{-1}$.Substituting the values:$\lambda = \frac{3.00 	imes 10^{8} \, m \, s^{-1}}{1368 	imes 10^{3} \, s^{-1}}$$\lambda = 219.3 \, m$Since the wavelength is in the range of meters,this radiation belongs to the radio wave region of the electromagnetic spectrum.

The Vividh Bharati station of All India Radio,Delhi,broadcasts on a frequency of $1368 \, kHz$ (kilo hertz). Calculate the wavelength of the electromagnetic radiation emitted by the transmitter. Which part of the electromagnetic spectrum does it belong to?

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