The viability of seeds is tested by

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(B) The correct answer is $B$. Viability of seeds can be determined by two primary methods: $(i)$ testing the ability to germinate,and $(ii)$ testing

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$2, 3, 5$-triphenyl tetrazolium chloride

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(B) The correct answer is $B$. Viability of seeds can be determined by two primary methods: $(i)$ testing the ability to germinate,and $(ii)$ testing the ability to respire. All living,viable seeds perform respiration. This metabolic activity can be tested by immersing a section of the seed containing the embryo in a $0.1\%$ solution of $2, 3, 5$-triphenyl tetrazolium chloride. In viable seeds,the dehydrogenase enzymes present in the living embryo reduce the colourless triphenyl tetrazolium chloride into an insoluble red-coloured dye called triphenyl formazan. Therefore,the embryo turns pink or red,indicating that the seed is viable.

List-$I$	List-$II$
$A.$ Scutellum	$I.$ Persistent nucellus
$B.$ Non-albuminous seed	$II.$ Cotyledon of Monocot seed
$C.$ Epiblast	$III.$ Groundnut
$D.$ Perisperm	$IV.$ Rudimentary cotyledon

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Match List-$I$ with List-$II$.
List-$I$ List-$II$
$A.$ Scutellum $I.$ Persistent nucellus
$B.$ Non-albuminous seed $II.$ Cotyledon of Monocot seed
$C.$ Epiblast $III.$ Groundnut
$D.$ Perisperm $IV.$ Rudimentary cotyledon
Choose the option with all correct matches.

In groundnut, the source of oil is found in:

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