The velocity$-$time graph of a truck is plotted below

$(a)$ Calculate the magnitude of displacement of the truck in $15$ seconds.

$(b)$ During which part of the journey was the truck decelerating ?

$(c)$ Calculate the magnitude of average velocity of the truck.

1151-116

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$(a)$ Displacement $=$ area under the velocitytime graph, therefore, we Kave

$=\frac{1}{2} \times 5 \times 4+(12-5) \times 4+\frac{1}{2} \times(15-12) \times 4$

$=44 m$

$(b)$ During $12$ to $15$ second.

$(c)$ $V _{a v}=\frac{\text { displacement }}{\text { time }}=\frac{44}{15}=2.9 m s ^{-1}$

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