The velocity$-$time graph of a truck is plotted below
$(a)$ Calculate the magnitude of displacement of the truck in $15$ seconds.
$(b)$ During which part of the journey was the truck decelerating ?
$(c)$ Calculate the magnitude of average velocity of the truck.
$(a)$ Displacement $=$ area under the velocitytime graph, therefore, we Kave
$=\frac{1}{2} \times 5 \times 4+(12-5) \times 4+\frac{1}{2} \times(15-12) \times 4$
$=44 m$
$(b)$ During $12$ to $15$ second.
$(c)$ $V _{a v}=\frac{\text { displacement }}{\text { time }}=\frac{44}{15}=2.9 m s ^{-1}$
Write any two equations of motion for a body having uniform acceleration.
What is the nature of the displacement$-$time graph of a body moving with constant velocity ?
What conclusion can you draw from the displacement$-$time graph of a body shown below ?
Distinguish between terms speed and velocity.
A girl running a race accelerates at $2.5\, m s ^{-2}$ for the first $4\, s$ of the race. How far does she travel in this time ?