The velocity-time graph for two bodies A and | vedclass

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(B) The acceleration of a body is given by the slope of its velocity-time graph.
Acceleration $a = \frac{dv}{dt} = 	an 	heta$,where $	heta$ is the

Vedclass · Accepted Answer

$	an 25^{\circ}$ to $	an 50^{\circ}$

Vedclass · Answer

(B) The acceleration of a body is given by the slope of its velocity-time graph.
Acceleration $a = \frac{dv}{dt} = 	an 	heta$,where $	heta$ is the angle the line makes with the time axis.
For body $A$,the angle with the time axis is $25^{\circ}$. Thus,$a_A = 	an 25^{\circ}$.
For body $B$,the angle with the time axis is $50^{\circ}$. Thus,$a_B = 	an 50^{\circ}$.
Therefore,the ratio of the acceleration of $A$ to the acceleration of $B$ is $\frac{a_A}{a_B} = \frac{	an 25^{\circ}}{	an 50^{\circ}}$.

The velocity-time graph for two bodies $A$ and $B$ is shown. Then the acceleration of $A$ and $B$ are in the ratio:

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