The vector equation of the plane which is at a distance of $ \frac{3}{\sqrt{14}} $ from the origin and the normal vector from the origin is $ 2 \hat{i}-3 \hat{j}+\hat{k} $ is:

  • A
    $ \vec{r} \cdot(2 \hat{i}-3 \hat{j}+\hat{k})=3 $
  • B
    $ \vec{r} \cdot(\hat{i}+\hat{j}+\hat{k})=9 $
  • C
    $ \vec{r} \cdot(\hat{i}+2 \hat{j})=3 $
  • D
    $ \vec{r} \cdot(2 \hat{i}+\hat{k})=3 $

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