The value of the resistor,R_S,needed in the d | vedclass

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(A) In the given $dc$ voltage regulator circuit,the total current flowing through the series resistor $R_S$ is the sum of the load current $I_L$ and t

Vedclass · Accepted Answer

$\frac{(V_i - V_L)}{(n + 1)I_L}$

Vedclass · Answer

(A) In the given $dc$ voltage regulator circuit,the total current flowing through the series resistor $R_S$ is the sum of the load current $I_L$ and the Zener diode current $I_Z$.From the circuit diagram,the Zener diode current is given as $I_Z = nI_L$.Therefore,the total current $I$ flowing through $R_S$ is $I = I_L + I_Z = I_L + nI_L = (n + 1)I_L$.The voltage drop across the resistor $R_S$ is $V_i - V_L$.Using Ohm's law,$V_i - V_L = I 	imes R_S$.Substituting the value of $I$,we get $V_i - V_L = (n + 1)I_L 	imes R_S$.Thus,the value of the resistor $R_S$ is $R_S = \frac{V_i - V_L}{(n + 1)I_L}$.

The value of the resistor,$R_S$,needed in the $dc$ voltage regulator circuit shown here,equals

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