The value of the following is cos 24^{circ} + | vedclass

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(B) We are given the expression: $\cos 24^{\circ} + \cos 55^{\circ} + \cos 125^{\circ} + \cos 204^{\circ} + \cos 300^{\circ}$.Rearranging the terms,we

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$\frac{1}{2}$

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(B) We are given the expression: $\cos 24^{\circ} + \cos 55^{\circ} + \cos 125^{\circ} + \cos 204^{\circ} + \cos 300^{\circ}$.Rearranging the terms,we get: $(\cos 24^{\circ} + \cos 204^{\circ}) + (\cos 55^{\circ} + \cos 125^{\circ}) + \cos 300^{\circ}$.Using the identity $\cos(180^{\circ} + 	heta) = -\cos 	heta$ and $\cos(180^{\circ} - 	heta) = -\cos 	heta$:$\cos 204^{\circ} = \cos(180^{\circ} + 24^{\circ}) = -\cos 24^{\circ}$.$\cos 125^{\circ} = \cos(180^{\circ} - 55^{\circ}) = -\cos 55^{\circ}$.For the last term,$\cos 300^{\circ} = \cos(360^{\circ} - 60^{\circ}) = \cos 60^{\circ} = \frac{1}{2}$.Substituting these values back into the expression:$(\cos 24^{\circ} - \cos 24^{\circ}) + (\cos 55^{\circ} - \cos 55^{\circ}) + \frac{1}{2} = 0 + 0 + \frac{1}{2} = \frac{1}{2}$.

The value of the following is $\cos 24^{\circ} + \cos 55^{\circ} + \cos 125^{\circ} + \cos 204^{\circ} + \cos 300^{\circ}$

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