The value of the 'spin only' magnetic moment | vedclass

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(A) The 'spin only' magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.For $\mu = 2.84 \

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$d^4$ (in strong ligand field)

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(A) The 'spin only' magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.For $\mu = 2.84 \ BM$,we have $\sqrt{n(n+2)} = 2.84$,which implies $n(n+2) \approx 8$,so $n = 2$.In a $d^4$ configuration with a strong ligand field,the electrons pair up in the $t_{2g}$ orbitals,resulting in $2$ unpaired electrons $(t_{2g}^4, e_g^0)$.Thus,$n = 2$ and $\mu = \sqrt{2(2+2)} = \sqrt{8} = 2.828 \approx 2.84 \ BM$.

The value of the 'spin only' magnetic moment for one of the following configurations is $2.84 \ BM$. The correct one is:

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