Identify the complex compound(s) which is/are | vedclass

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(A) To be optically active,a complex must lack a plane of symmetry and a center of inversion.$(i). [CoCl_3(NH_3)_3]$: Both $fac$ and $mer$ isomers are

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only $(ii)$

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(A) To be optically active,a complex must lack a plane of symmetry and a center of inversion.$(i). [CoCl_3(NH_3)_3]$: Both $fac$ and $mer$ isomers are optically inactive due to the presence of planes of symmetry.$(ii). [Co(en)_3]Cl_3$: This complex contains three bidentate ligands $(en)$. It exists as a pair of enantiomers ($d$ and $l$ forms). Since it has no geometric isomers,its optical activity is independent of ligand orientation.$(iii). [Co(C_2O_4)_2(NH_3)_2]^-$: This complex shows geometric isomerism ($cis$ and $trans$). The $cis$-isomer is optically active,while the $trans$-isomer is optically inactive. Thus,its activity depends on orientation.$(iv). [CrCl_2(NH_3)_2(en)]^+$: This complex exhibits geometric isomerism. Depending on the arrangement of $Cl$ and $NH_3$ ligands,some isomers are optically active while others are not. Thus,its activity depends on orientation.Therefore,only $(ii)$ is optically active and independent of ligand orientation.

List-$I$ (Coordination compounds)	List-$II$ (Number of unpaired electrons)
$A$. $[Cr(CN)_6]^{3-}$	$I$. $0$
$B$. $[Fe(H_2O)_6]^{2+}$	$II$. $3$
$C$. $[Co(NH_3)_6]^{3+}$	$III$. $2$
$D$. $[Ni(NH_3)_6]^{2+}$	$IV$. $4$

Identify the complex compound$(s)$ which is/are optically active and whose optical activity does not depend upon the orientation of the ligands around the metal cation:
$(i). [CoCl_3(NH_3)_3]$
$(ii). [Co(en)_3]Cl_3$
$(iii). [Co(C_2O_4)_2(NH_3)_2]^-$
$(iv). [CrCl_2(NH_3)_2(en)]^+$

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Identify the complex compound$(s)$ which is/are optically active and whose optical activity does not depend upon the orientation of the ligands around the metal cation:$(i). [CoCl_3(NH_3)_3]$$(ii). [Co(en)_3]Cl_3$$(iii). [Co(C_2O_4)_2(NH_3)_2]^-$$(iv). [CrCl_2(NH_3)_2(en)]^+$