The value of power dissipated across the Zener diode $(V_{Z} = 15 \text{ V})$ connected in the circuit as shown in the figure is $x \times 10^{-1} \text{ watt}$. The value of $x$, to the nearest integer, is ..............

In the given circuit, if the power rating of the Zener diode is $10 \, mW$, the value of series resistance $R_s$ to regulate the input unregulated supply is:

$A$ Zener diode of breakdown voltage $V_{Z} = 8\,V$ and maximum Zener current $I_{ZM} = 10\,mA$ is subjected to an input voltage $V_{i} = 10\,V$ with a series resistance $R = 100\,\Omega$. In the given circuit,$R_{L}$ represents the variable load resistance. The ratio of the maximum and minimum value of $R_{L}$ is

$A$ Zener diode with $5\ V$ Zener voltage is used to regulate an unregulated $DC$ voltage input of $25\ V$. For a $400\ \Omega$ resistor connected in series, the Zener current is found to be $4$ times the load current. The load current $(I_L)$ and load resistance $(R_L)$ are:

In the given circuit,the Zener breakdown voltage is $8 \ V$. If the power of the Zener diode is $1.6 \ W$,the value of $R$ is (in $\Omega$)

In the given circuit, find the voltage drop $V_L$ across the load resistance $R_L$. (in $V$)