The value of discriminant D for the equation | vedclass

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Question

(A) Given the equation $(x+2)(x-5)=0$.Expanding the brackets: $x^2 - 5x + 2x - 10 = 0$.This simplifies to the standard quadratic form: $x^2 - 3x - 10

Vedclass · Accepted Answer

$49$

Vedclass · Answer

(A) Given the equation $(x+2)(x-5)=0$.Expanding the brackets: $x^2 - 5x + 2x - 10 = 0$.This simplifies to the standard quadratic form: $x^2 - 3x - 10 = 0$.Comparing this with the standard form $ax^2 + bx + c = 0$,we get $a=1$,$b=-3$,and $c=-10$.The discriminant $D$ is given by the formula $D = b^2 - 4ac$.Substituting the values: $D = (-3)^2 - 4(1)(-10)$.$D = 9 + 40 = 49$.

The value of discriminant $D$ for the equation $(x+2)(x-5)=0$ is ............

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