The value of x in compound 'D' is .......... | vedclass

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(B) The starting material is $4$-ethoxyphenylacetaldehyde. $1$. Strecker synthesis: Reaction with $NH_4Cl/KCN$ followed by hydrolysis gives $4$-ethoxy

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(B) The starting material is $4$-ethoxyphenylacetaldehyde. $1$. Strecker synthesis: Reaction with $NH_4Cl/KCN$ followed by hydrolysis gives $4$-ethoxyphenylalanine ('$A$'). $2$. Nitration: Treatment with $Conc. HNO_3-H_2SO_4$ $(2 \ eq)$ introduces two nitro groups at the ortho positions relative to the ethoxy group,yielding $3,5$-dinitro-$4$-ethoxyphenylalanine ('$B$'). $3$. Acetylation: Reaction with $(CH_3CO)_2O$ protects the amino group as an acetamide. $4$. Esterification: Reaction with $EtOH/\Delta$ converts the carboxylic acid to an ethyl ester. $5$. Reduction: $H_2, Pd/C$ reduces the two nitro groups to amino groups. $6$. Diazotization: $HNO_2$ converts the amino groups to diazonium salts. $7$. Sandmeyer-like reaction: $NaI$ replaces the diazonium groups with iodine atoms. The final product '$D$' is $3,5$-diiodo-$4$-ethoxyphenylalanine ethyl ester derivative. The molecular formula is $C_{15}H_{19}NO_4I_2$. Comparing this with $C_xH_{19}NO_4I_2$,we find $x = 15$.

The value of $x$ in compound '$D$' is $.........$.

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