The value of $\tan 15^{\circ}$ and $\ldots \ldots \ldots \ldots$ are equal.
- A$\cot 15^{\circ}$
- B$\cot 75^{\circ}$
- C$\sec 15^{\circ}$
- D$\tan 75^{\circ}$
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Similar Questions
Which of the following pairs is correct for trigonometric inter-relationships?
$1. \cos \theta$ $a. \frac{\cos \theta}{\sin \theta}$ $2. \tan \theta$ $b. \frac{1}{\csc \theta}$ $3. \cot \theta$ $c. \frac{1}{\sec \theta}$ $4. \sin \theta$ $d. \frac{1}{\cot \theta}$ $e. \sin \theta \cdot \cos \theta$
| $1. \cos \theta$ | $a. \frac{\cos \theta}{\sin \theta}$ |
| $2. \tan \theta$ | $b. \frac{1}{\csc \theta}$ |
| $3. \cot \theta$ | $c. \frac{1}{\sec \theta}$ |
| $4. \sin \theta$ | $d. \frac{1}{\cot \theta}$ |
| $e. \sin \theta \cdot \cos \theta$ |
Easy
View SolutionFor acute angles $A$ and $B,$ if $\tan A = 1$ and $\sin B = \frac{1}{\sqrt{2}},$ then $\cos (A + B) = \dots$
Easy
View Solution$\sec (90^\circ - \theta) = \dots$
Easy
View Solution$0 < \theta < 90$ and $\sec \theta = \operatorname{cosec} 60^\circ$,then the value of $2 \cos^2 \theta - 1$ is ........
Medium
View SolutionIf $A+B+C=180^{\circ},$ then $\tan \left(\frac{A+B}{2}\right)=$ ...........
Medium
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