The value of sin ^{2} 22^{circ}+sin ^{2} 68^{ | vedclass

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(B) Given expression: $\sin ^{2} 22^{\circ}+\sin ^{2} 68^{\circ}+\cot ^{2} 30^{\circ}$We know that $\sin(90^{\circ}-	heta) = \cos 	heta$.Therefore,$

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$4$

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(B) Given expression: $\sin ^{2} 22^{\circ}+\sin ^{2} 68^{\circ}+\cot ^{2} 30^{\circ}$We know that $\sin(90^{\circ}-	heta) = \cos 	heta$.Therefore,$\sin 22^{\circ} = \sin(90^{\circ}-68^{\circ}) = \cos 68^{\circ}$.Substituting this into the expression,we get:$\cos ^{2} 68^{\circ} + \sin ^{2} 68^{\circ} + \cot ^{2} 30^{\circ}$Using the identity $\sin ^{2} 	heta + \cos ^{2} 	heta = 1$,we have:$1 + \cot ^{2} 30^{\circ}$Since $\cot 30^{\circ} = \sqrt{3}$,then $\cot ^{2} 30^{\circ} = (\sqrt{3})^{2} = 3$.Thus,the value is $1 + 3 = 4$.

The value of $\sin ^{2} 22^{\circ}+\sin ^{2} 68^{\circ}+\cot ^{2} 30^{\circ}$ is:

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