The value of sqrt{frac{(0.03)^{2}+(0.21)^{2}+ | vedclass

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(B) We are given the expression: $\sqrt{\frac{(0.03)^{2}+(0.21)^{2}+(0.065)^{2}}{(0.003)^{2}+(0.021)^{2}+(0.0065)^{2}}}$Notice that each term in the n

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(B) We are given the expression: $\sqrt{\frac{(0.03)^{2}+(0.21)^{2}+(0.065)^{2}}{(0.003)^{2}+(0.021)^{2}+(0.0065)^{2}}}$Notice that each term in the numerator is $10$ times the corresponding term in the denominator: $0.03 = 10 	imes 0.003$,$0.21 = 10 	imes 0.021$,and $0.065 = 10 	imes 0.0065$.Substituting these into the numerator: $(0.03)^{2} = (10 	imes 0.003)^{2} = 10^{2} 	imes (0.003)^{2}$,$(0.21)^{2} = 10^{2} 	imes (0.021)^{2}$,and $(0.065)^{2} = 10^{2} 	imes (0.0065)^{2}$.Factoring out $10^{2}$ from the numerator: $\sqrt{\frac{10^{2} \left[(0.003)^{2} + (0.021)^{2} + (0.0065)^{2}ight]}{(0.003)^{2} + (0.021)^{2} + (0.0065)^{2}}}$The terms in the brackets cancel out: $\sqrt{10^{2}} = 10$.

The value of $\sqrt{\frac{(0.03)^{2}+(0.21)^{2}+(0.065)^{2}}{(0.003)^{2}+(0.021)^{2}+(0.0065)^{2}}}$ is

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