The unit of permeability of vacuum (mu_{0}) i | vedclass

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(B) The magnetic force per unit length between two parallel current-carrying wires is given by the formula: $F/L = \frac{\mu_{0} I_{1} I_{2}}{2 \pi d}

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$\frac{N}{A^{2}}$

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(B) The magnetic force per unit length between two parallel current-carrying wires is given by the formula: $F/L = \frac{\mu_{0} I_{1} I_{2}}{2 \pi d}$.Rearranging for $\mu_{0}$,we get: $\mu_{0} = \frac{(F/L) \cdot 2 \pi d}{I_{1} I_{2}}$.The $SI$ unit of force $(F)$ is Newton $(N)$,length $(L)$ is meter $(m)$,distance $(d)$ is meter $(m)$,and current $(I)$ is Ampere $(A)$.Substituting the units: $	ext{Unit of } \mu_{0} = \frac{(N/m) \cdot m}{A \cdot A} = \frac{N}{A^{2}}$.Alternatively,since $1 	ext{ Tesla} = 1 	ext{ N}/(A \cdot m)$,the unit can also be expressed as $T \cdot m/A$ or $Wb/(A \cdot m)$.

The unit of permeability of vacuum $(\mu_{0})$ is . . . . . . .

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