The type of hybridisation and number of lone | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the hybridisation and lone pairs of $Xe$ in $XeOF_4$:$1$. The central atom is $Xe$,which has $8$ valence electrons.$2$. $Xe$ forms $4

Vedclass · Accepted Answer

$sp^3d^2$ and $1$

Vedclass · Answer

(A) To determine the hybridisation and lone pairs of $Xe$ in $XeOF_4$:$1$. The central atom is $Xe$,which has $8$ valence electrons.$2$. $Xe$ forms $4$ single bonds with $F$ atoms and $1$ double bond with the $O$ atom.$3$. Total number of electron pairs around $Xe$ = (Number of sigma bonds) + (Number of lone pairs).$4$. $Xe$ forms $5$ sigma bonds ($4$ with $F$ and $1$ with $O$) and $1$ pi bond with $O$.$5$. The number of lone pairs on $Xe$ = (Total valence electrons - Electrons used in bonding) / $2$ = $(8 - (4 	imes 1 + 1 	imes 2)) / 2 = (8 - 6) / 2 = 1$ lone pair.$6$. Steric number = (Number of sigma bonds) + (Number of lone pairs) = $5 + 1 = 6$.$7$. $A$ steric number of $6$ corresponds to $sp^3d^2$ hybridisation.$8$. Therefore,the hybridisation is $sp^3d^2$ and the number of lone pairs is $1$.

The type of hybridisation and number of lone pair$(s)$ of electrons of $Xe$ in $XeOF_4$ respectively are

Similar Questions

Assertion $(A)$: The boiling points of noble gases increase from $He$ to $Xe$.
Reason $(R)$: The interatomic van der Waals' attractive forces increase from $He$ to $Xe$.
The correct answer is:

Which of the following is not obtained by the direct reaction of constituent elements?

Which one of the following reactions of xenon compounds is not feasible?

Which of the following statements is $NOT$ correct regarding $Helium$?

$XeF_2 + H_2O \to$ Products (The possible products are)

Vedclass Test Series

Exam Paper Generator

Online Exam Module