(B) In an $HCl$ molecule,the electronegativity difference between $H$ $(2.1)$ and $Cl$ $(3.0)$ is approximately $0.9$. Because the electronegativity d

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(B) In an $HCl$ molecule,the electronegativity difference between $H$ $(2.1)$ and $Cl$ $(3.0)$ is approximately $0.9$. Because the electronegativity difference is greater than $0$ but less than $1.7$,the bond formed is a polar covalent bond,where the shared pair of electrons is shifted towards the more electronegative chlorine atom.