The two waves represented by y_1 = a sin(omeg | vedclass

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(B) Given the wave equations:$y_1 = a \sin(\omega t)$$y_2 = b \cos(\omega t)$Using the trigonometric identity $\cos(	heta) = \sin(	heta + \frac{\pi}

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$\frac{\pi}{2}$

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(B) Given the wave equations:$y_1 = a \sin(\omega t)$$y_2 = b \cos(\omega t)$Using the trigonometric identity $\cos(	heta) = \sin(	heta + \frac{\pi}{2})$,we can rewrite $y_2$ as:$y_2 = b \sin(\omega t + \frac{\pi}{2})$The phase of the first wave is $\phi_1 = \omega t$.The phase of the second wave is $\phi_2 = \omega t + \frac{\pi}{2}$.The phase difference $\Delta\phi$ is given by $\phi_2 - \phi_1 = (\omega t + \frac{\pi}{2}) - \omega t = \frac{\pi}{2}$.

The two waves represented by $y_1 = a \sin(\omega t)$ and $y_2 = b \cos(\omega t)$ have a phase difference of

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