The truth table for the following logic circu | vedclass

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Question

(A) The given circuit consists of two $NOT$ gates, two $AND$ gates, and one $OR$ gate. The inputs are $A$ and $B$. The output of the top $AND$ gate is

Vedclass · Accepted Answer

$A = 0$, $B = 0$, $Y = 0$; $A = 0$, $B = 1$, $Y = 1$; $A = 1$, $B = 0$, $Y = 1$; $A = 1$, $B = 1$, $Y = 0$

Vedclass · Answer

(A) The given circuit consists of two $NOT$ gates, two $AND$ gates, and one $OR$ gate. The inputs are $A$ and $B$. The output of the top $AND$ gate is $\bar{A} \cdot B$ and the output of the bottom $AND$ gate is $A \cdot \bar{B}$. These are fed into an $OR$ gate, so the final output is $Y = \bar{A} \cdot B + A \cdot \bar{B}$. This is the Boolean expression for an $XOR$ gate. The truth table is as follows:$A$$B$$Y$$0$$0$$0$$0$$1$$1$$1$$0$$1$$1$$1$$0$

The truth table for the following logic circuit is

Similar Questions

Which logic gate with inputs $A$ and $B$ performs the same operation as that performed by the following circuit?

Which of the following circuits has the same output as that of the given circuit?

The given truth table is correct for:
$P: 1, 1, 0, 0$
$Q: 1, 0, 1, 0$
$R: 1, 0, 0, 0$

For the given logic circuit,what should be the value of input $ABC$ to get an output $Y = 1$?

The truth table for the given circuit is

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