The transmitting antenna placed at the top of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for the maximum line-of-sight distance $d$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is g

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(C) The formula for the maximum line-of-sight distance $d$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is given by $d = \sqrt{2Rh_T} + \sqrt{2Rh_R}$,where $R$ is the radius of the Earth.Given: $h_T = 45 \ m = 0.045 \ km$,$d = 40 \ km$,and $R = 6400 \ km$.Substituting the values into the formula:$40 = \sqrt{2 	imes 6400 	imes 0.045} + \sqrt{2 	imes 6400 	imes h_R}$$40 = \sqrt{12800 	imes 0.045} + \sqrt{12800 	imes h_R}$$40 = \sqrt{576} + \sqrt{12800 	imes h_R}$$40 = 24 + \sqrt{12800 	imes h_R}$$16 = \sqrt{12800 	imes h_R}$Squaring both sides:$256 = 12800 	imes h_R$$h_R = \frac{256}{12800} \ km = 0.02 \ km$Converting to meters: $h_R = 0.02 	imes 1000 \ m = 20 \ m$.

Similar Questions

For the output of an $AM$ detector circuit to follow the envelope of the carrier wave,which condition must be satisfied? ($T_c$ is the time period of the carrier wave.)

The range of frequency bands used for standard $AM$ broadcast is

In amplitude modulation,the amplitude of the $.......$ wave varies in proportion to the instantaneous value of the $.......$ wave.

The maximum distance up to which $TV$ transmission from a $TV$ tower of height $h$ can be received is proportional to

The relationship between the maximum electron density $(N_{max})$ of the ionosphere and the critical frequency $(f_c)$ is given by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module