The translational kinetic energy of the molecules of a gas at absolute temperature $T$ can be doubled by:

If the $r.m.s.$ velocity of a gas is $v_{rms} = 1840 \ m/s$ and its density is $\rho = 8.99 \times 10^{-2} \ kg/m^3$,what is the pressure of the gas?

According to the kinetic theory of gases,

Two gases $A$ and $B$ are at absolute temperatures $350 \ K$ and $420 \ K$ respectively. The ratio of average kinetic energy of the molecules of gas $B$ to that of gas $A$ is

The relation between the pressure $(P)$,volume $(V)$,and average kinetic energy $(E)$ of a gas is

Number of molecules in a volume of $4\, cm^{3}$ of a perfect monoatomic gas at some temperature $T$ and at a pressure of $2\, cm$ of mercury is close to $?$
(Given,mean kinetic energy of a molecule (at $T$) is $4 \times 10^{-14}\, erg$,$g=980\, cm/s^{2}$,density of mercury $=13.6\, g/cm^{3}$)