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(A) To find the total number of unpaired electrons,we analyze the electronic configuration in an octahedral field for each case:$1$. $d^3$: The config

Vedclass · Accepted Answer

$15$

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(A) To find the total number of unpaired electrons,we analyze the electronic configuration in an octahedral field for each case:$1$. $d^3$: The configuration is $t_{2g}^3 e_g^0$. Number of unpaired electrons = $3$.$2$. $d^4$ (low spin): The configuration is $t_{2g}^4 e_g^0$. Number of unpaired electrons = $2$.$3$. $d^5$ (high spin): The configuration is $t_{2g}^3 e_g^2$. Number of unpaired electrons = $5$.$4$. $d^6$ (high spin): The configuration is $t_{2g}^4 e_g^2$. Number of unpaired electrons = $4$.$5$. $d^7$ (low spin): The configuration is $t_{2g}^6 e_g^1$. Number of unpaired electrons = $1$.Sum = $3 + 2 + 5 + 4 + 1 = 15$.

The total number of unpaired electrons present in the $d^3$,$d^4$ (low spin),$d^5$ (high spin),$d^6$ (high spin),and $d^7$ (low spin) octahedral complex systems is . . . . . . .

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