The total number of unpaired electrons presen | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For $[Co(NH_3)_6]Cl_2$:$Co$ is in $+2$ oxidation state. The electronic configuration of $Co^{2+}$ is $[Ar] 3d^7$.Since $NH_3$ is a weak field liga

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) For $[Co(NH_3)_6]Cl_2$:$Co$ is in $+2$ oxidation state. The electronic configuration of $Co^{2+}$ is $[Ar] 3d^7$.Since $NH_3$ is a weak field ligand for $Co^{2+}$,no pairing occurs.The configuration is $t_{2g}^5 e_g^2$,resulting in $3$ unpaired electrons.For $[Co(NH_3)_6]Cl_3$:$Co$ is in $+3$ oxidation state. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since $NH_3$ is a strong field ligand for $Co^{3+}$,pairing occurs.The configuration is $t_{2g}^6 e_g^0$,resulting in $0$ unpaired electrons.Total number of unpaired electrons = $3 + 0 = 3$.

Hybridisation	Geometry	Complex structure
$(A) \ sp^3$	$(i) \ \text{Square planar}$	$(p) \ [Fe(CN)_6]^{3-}$
$(B) \ d^2sp^3$	$(ii) \ \text{Tetrahedral}$	$(q) \ [ZnCl_4]^{2-}$
$(C) \ dsp^2$	$(iii) \ \text{Octahedral}$	$(r) \ [Ni(NH_3)_4]^{2+}$
-	$(iv) \ \text{Linear}$	$(s) \ [Ag(CN)_2]^-$

The total number of unpaired electrons present in $[Co(NH_3)_6]Cl_2$ and $[Co(NH_3)_6]Cl_3$ is $......$

Similar Questions

Draw the structure of the $[Cr(CO)_6]$ complex.

The correct statement among the following is:

The shape of $MnO_4^-$ ion and the hybridisation of $Mn$ in $MnO_4^-$ is

What is the type of hybridization of $Ag$ in the linear complex $[Ag(NH_3)_2]^+$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module