(C) The structural isomeric alcohols with the molecular formula $C_4H_{10}O$ are: $1.$ Butan$-1-$ol: $CH_3CH_2CH_2CH_2OH$ $2.$ Butan$-2-$ol: $CH_3CH_2

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(C) The structural isomeric alcohols with the molecular formula $C_4H_{10}O$ are: $1.$ Butan$-1-$ol: $CH_3CH_2CH_2CH_2OH$ $2.$ Butan$-2-$ol: $CH_3CH_2CH(OH)CH_3$ $3.$ $2-$Methylpropan$-1-$ol: $(CH_3)_2CHCH_2OH$ $4.$ $2-$Methylpropan$-2-$ol: $(CH_3)_3COH$ Thus,the total number of structural isomers is $4$.