The total number of possible isomers of the c | vedclass

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(C) The given complex $[Cu(NH_3)_4][PtCl_4]$ exhibits coordination isomerism.The possible coordination isomers are formed by the exchange of ligands b

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) The given complex $[Cu(NH_3)_4][PtCl_4]$ exhibits coordination isomerism.The possible coordination isomers are formed by the exchange of ligands between the cationic and anionic coordination spheres:$1. [Cu(NH_3)_4][PtCl_4]$$2. [Cu(NH_3)_3Cl][Pt(NH_3)Cl_3]$$3. [Cu(NH_3)_2Cl_2][Pt(NH_3)_2Cl_2]$$4. [Cu(NH_3)Cl_3][Pt(NH_3)_3Cl]$$5. [CuCl_4][Pt(NH_3)_4]$Thus,there are a total of $5$ possible isomers.

The total number of possible isomers of the complex compound $[Cu(NH_3)_4] [PtCl_4]$ is:

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