The total number of possible isomers for the complex compound $[Cu^{II}(NH_3)_4][Pt^{II}Cl_4]$ are

  • A
    $60$
  • B
    $7$
  • C
    $5$
  • D
    $6$

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Similar Questions

Number of stereoisomers possible for the octahedral complexes $[Co(NH_3)_3Cl_3]$ and $[Ni(en)_2Cl_2]$,respectively,are (where $en = 1,2-$ethylenediamine):

$[Co(NH_3)_5SO_4]Br$ and $[Co(NH_3)_5Br]SO_4$ are a pair of isomers.

Match the List-$I$ with List-$II$:
List-$I$ (Complex ion)List-$II$ (Calculated spin only magnetic moment $(BM)$)
$A$. $[Cr(H_2O)_6]^{2+}$$I$. $3.87$
$B$. $[Co(H_2O)_6]^{2+}$$II$. $5.92$
$C$. $[Cu(H_2O)_6]^{2+}$$III$. $4.90$
$D$. $[Mn(H_2O)_6]^{2+}$$IV$. $1.73$

Choose the correct answer from the options given below:

The possible number of stereoisomers for $[Co(en)_2Cl_2]^+$ is

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Which of the following compounds is diamagnetic?

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