The total number of possible isomers for [Pt( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The complex $[Pt(NH_3)_4Cl_2]Br_2$ exhibits ionization isomerism.Possible ionization isomers are:$1$. $[Pt(NH_3)_4Cl_2]Br_2$ (Geometrical isomers:

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) The complex $[Pt(NH_3)_4Cl_2]Br_2$ exhibits ionization isomerism.Possible ionization isomers are:$1$. $[Pt(NH_3)_4Cl_2]Br_2$ (Geometrical isomers: $cis$ and $trans$,so $2$ isomers)$2$. $[Pt(NH_3)_4ClBr]ClBr$ (Geometrical isomers: $cis$ and $trans$,so $2$ isomers)$3$. $[Pt(NH_3)_4Br_2]Cl_2$ (Geometrical isomers: $cis$ and $trans$,so $2$ isomers)Each ionization isomer has $2$ geometrical isomers.Total isomers = $2 + 2 + 2 = 6$.

The total number of possible isomers for $[Pt(NH_3)_4Cl_2]Br_2$ is . . . . . . .

Similar Questions

Of the following,which is diamagnetic in nature?

Total number of relatively more stable isomer$(s)$ possible for octahedral complex $[Cu(en)_2(SCN)_2]$ will be $.........$

$[Co(NH_3)Cl(en)_2]^{2+}$ shows two geometrical isomers,$cis$ and $trans$. Which of the following statements is correct?

Which one of the following does not exhibit geometrical isomerism?

How many optical isomers are possible for the complex $[Pt(NH_3)_2(CN)_2]$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module