The total number of optically active compound | vedclass

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(C) The reaction of the given vinyl ether with $HBr$ involves the protonation of the double bond followed by the nucleophilic attack of $Br^-$ to form

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$4$

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(C) The reaction of the given vinyl ether with $HBr$ involves the protonation of the double bond followed by the nucleophilic attack of $Br^-$ to form a bromo-ether product.The product formed has two chiral centers.For a molecule with $n$ chiral centers,the maximum number of stereoisomers is $2^n$.Here,$n = 2$,so there are $2^2 = 4$ stereoisomers.Since all four stereoisomers are chiral (optically active),the total number of optically active compounds formed is $4$.

The total number of optically active compounds formed in the following reaction is
$CH_3CH_2C(CH_3)=CHOCH(CH_3)_2$ $\xrightarrow{HBr}$

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The total number of optically active compounds formed in the following reaction is$CH_3CH_2C(CH_3)=CHOCH(CH_3)_2$ $\xrightarrow{HBr}$