The total number of electrons around the carbon atom of a methyl free radical is:

  • A
    $6$
  • B
    $8$
  • C
    $7$
  • D
    $9$

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The order of stability of the following carbocations is:
$I$. $CH_2 = CH - CH_2^+$
$II$. $CH_3 - CH_2 - CH_2^+$
$III$. $C_6H_5CH_2^+$

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