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(B) The molecular formula $C_4H_6$ corresponds to a degree of unsaturation (double bond equivalent) of $4 - (6/2) + 1 = 2$. For cyclic isomers,we cons

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$5$

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(B) The molecular formula $C_4H_6$ corresponds to a degree of unsaturation (double bond equivalent) of $4 - (6/2) + 1 = 2$. For cyclic isomers,we consider structures with one ring and one double bond,or two rings. The possible cyclic isomers are: $1$. Cyclobutene $2$. $1-$Methylcyclopropene $3$. $3-$Methylcyclopropene $4$. Methylenecyclopropane $5$. Bicyclobutane Thus,there are a total of $5$ cyclic isomers.

The total number of cyclic isomers possible for a hydrocarbon with the molecular formula $C_4H_6$ is

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