The time period of a second's pendulum is 2, | vedclass

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(C) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g}}$,where $l$ is the length of the pendulum and $g$ is the

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$2$

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(C) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g}}$,where $l$ is the length of the pendulum and $g$ is the acceleration due to gravity.From this formula,it is clear that the time period $T$ is independent of the mass of the bob.Since the length of the pendulum remains unchanged,the time period will remain the same regardless of the change in mass of the bob.Therefore,the new time period is $2\, s$.

The time period of a second's pendulum is $2\, s$. The spherical bob,which is empty from inside,has a mass of $50\, g$. This is now replaced by another solid bob of the same radius but having a mass of $100\, g$. The new time period will be .... $s$.

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