The time average of the kinetic energy of one | vedclass

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(B) According to the kinetic theory of gases,the average kinetic energy $(E)$ of a single molecule of an ideal gas is given by the formula: $E = \frac

Vedclass · Accepted Answer

Is proportional to the absolute temperature of the gas

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(B) According to the kinetic theory of gases,the average kinetic energy $(E)$ of a single molecule of an ideal gas is given by the formula: $E = \frac{3}{2}kT$,where $k$ is the Boltzmann constant and $T$ is the absolute temperature of the gas.From this relation,it is evident that the average kinetic energy is directly proportional to the absolute temperature of the gas $(E \propto T)$.Therefore,the correct option is $B$.

The time average of the kinetic energy of one molecule of a gas taken over a long period of time:

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