(D) For photoelectric emission to occur,the incident radiation must have a wavelength $\lambda$ less than or equal to the threshold wavelength $\lambd

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) For photoelectric emission to occur,the incident radiation must have a wavelength $\lambda$ less than or equal to the threshold wavelength $\lambda_0$.Given $\lambda_0 = 5500\,\mathring A$.Infra-red radiation has wavelengths greater than $7000\,\mathring A$,which is greater than $5500\,\mathring A$. Thus,it cannot cause photoelectric emission.Ultra-violet radiation has wavelengths typically between $100\,\mathring A$ and $4000\,\mathring A$,which is less than $5500\,\mathring A$. Thus,it can cause photoelectric emission regardless of the power of the lamp.Therefore,both the $75\,W$ and $10\,W$ ultra-violet lamps will cause emission.The correct option is $D$ ($C$ and $D$ only).

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

Medium

The threshold wavelength for photoelectric emission from a material is $5500\,\mathring A$. Photoelectrons will be emitted when this material is illuminated with monochromatic radiation from a:
$A.$ $75\,W$ infra-red lamp
$B.$ $10\,W$ infra-red lamp
$C.$ $75\,W$ ultra-violet lamp
$D.$ $10\,W$ ultra-violet lamp
Choose the correct answer from the options given below:

JEE MAIN 2023 All JEE MAIN

A
$B$ and $C$ only
B
$A$ and $D$ only
C
$C$ only
D
$C$ and $D$ only

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Dual Nature of Radiation and matter

Subtopic

Einstein's Photoelectric Equation and Energy Quantum of Radiation

Previous Year

JEE MAIN 2023 Paper All JEE MAIN years →

At an incident radiation frequency of $v_1$,which is greater than the threshold frequency,the stopping potential for a certain metal is $V_1$. At frequency $2 v_1$,the stopping potential is $3 V_1$. If the stopping potential at frequency $4 v_1$ is $n V_1$,then $n$ is

MediumTS EAMCET 2018

View Solution

The difference between threshold wavelengths for two metal surfaces $A$ and $B$ having work functions $\phi_A = 9 \, eV$ and $\phi_B = 4.5 \, eV$ in $nm$ is: (Given,$hc = 1242 \, eV \, nm$)

EasyJEE MAIN 2023

View Solution

When a photon of energy $4.25\, eV$ strikes the surface of a metal $A$,the ejected photoelectrons have a maximum kinetic energy $T_A\, eV$ and de-Broglie wavelength ${\lambda _A}$. The maximum kinetic energy of photoelectrons liberated from another metal $B$ by a photon of energy $4.70\, eV$ is ${T_B} = ({T_A} - 1.50)\, eV$. If the de-Broglie wavelength of these photoelectrons is ${\lambda _B} = 2{\lambda _A}$,then:

DifficultIIT 1994

View Solution

When light is incident on a surface, photoelectrons are emitted. For photoelectrons:

Easy

View Solution

$A$ certain metallic surface is illuminated by monochromatic radiation of wavelength $\lambda$. The stopping potential for photoelectric current for this radiation is $3V_{0}$. If the same surface is illuminated with a radiation of wavelength $2\lambda$,the stopping potential is $V_{0}$. The threshold wavelength of this surface for the photoelectric effect is $n\lambda$. Find the value of $n$.

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

At an incident radiation frequency of $v_1$,which is greater than the threshold frequency,the stopping potential for a certain metal is $V_1$. At frequency $2 v_1$,the stopping potential is $3 V_1$. If the stopping potential at frequency $4 v_1$ is $n V_1$,then $n$ is

The difference between threshold wavelengths for two metal surfaces $A$ and $B$ having work functions $\phi_A = 9 \, eV$ and $\phi_B = 4.5 \, eV$ in $nm$ is: (Given,$hc = 1242 \, eV \, nm$)

When light is incident on a surface, photoelectrons are emitted. For photoelectrons:

Vedclass Test Series

Exam Paper Generator

Online Exam Module