The Thomson coefficient of a conductor is 10 | vedclass

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(D) The heat absorbed due to the Thomson effect is given by the formula: $H = \sigma q \Delta T$,where $\sigma$ is the Thomson coefficient,$q$ is the

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$1 	ext{ } mJ$

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(D) The heat absorbed due to the Thomson effect is given by the formula: $H = \sigma q \Delta T$,where $\sigma$ is the Thomson coefficient,$q$ is the charge,and $\Delta T$ is the temperature difference.Given:$\sigma = 10 \mu V/K = 10 	imes 10^{-6} 	ext{ } V/K$$q = 10 	ext{ } C$$\Delta T = 60^{\circ}C - 50^{\circ}C = 10 	ext{ } K$Substituting the values:$H = (10 	imes 10^{-6} 	ext{ } V/K) 	imes (10 	ext{ } C) 	imes (10 	ext{ } K)$$H = 1000 	imes 10^{-6} 	ext{ } J$$H = 10^{-3} 	ext{ } J = 1 	ext{ } mJ$.

The Thomson coefficient of a conductor is $10 \mu V/K$. The two ends of the conductor are maintained at $50^{\circ}C$ and $60^{\circ}C$,respectively. The amount of heat absorbed by the conductor when a charge of $10 C$ flows through it is:

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