The number of tetrahedral voids present in 0. | vedclass

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(B) In an $hcp$ crystal structure,the number of tetrahedral voids is equal to twice the number of atoms present in the lattice.Let $N$ be the number o

Vedclass · Accepted Answer

$6.02 	imes 10^{23}$

Vedclass · Answer

(B) In an $hcp$ crystal structure,the number of tetrahedral voids is equal to twice the number of atoms present in the lattice.Let $N$ be the number of atoms in the crystal.Number of atoms in $0.5 	ext{ mole} = 0.5 	imes N_A = 0.5 	imes 6.022 	imes 10^{23} = 3.011 	imes 10^{23} 	ext{ atoms}$.Number of tetrahedral voids $= 2 	imes 	ext{Number of atoms} = 2 	imes 3.011 	imes 10^{23} = 6.022 	imes 10^{23}$.Thus,the correct option is $B$.

The number of tetrahedral voids present in $0.5 \text{ mole}$ of an $hcp$ crystal structure is:

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