The temperature at which the speed of sound i | vedclass

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(C) The speed of sound in a gas is given by $v = \sqrt{\frac{\gamma RT}{M}}$,which implies $v \propto \sqrt{T}$.Given that the initial temperature $T_

Vedclass · Accepted Answer

$1092$

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(C) The speed of sound in a gas is given by $v = \sqrt{\frac{\gamma RT}{M}}$,which implies $v \propto \sqrt{T}$.Given that the initial temperature $T_1 = 0^oC = 273 \ K$.Let the initial speed be $v_1$ and the final speed be $v_2 = 2v_1$.Using the relation $\frac{v_2}{v_1} = \sqrt{\frac{T_2}{T_1}}$,we get:$2 = \sqrt{\frac{T_2}{273}}$.Squaring both sides,we get $4 = \frac{T_2}{273}$.Therefore,$T_2 = 4 	imes 273 = 1092 \ K$.

The temperature at which the speed of sound in air becomes double of its value at $0^oC$ is ...... $K$.

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