The surface areas of two nuclei are in the ratio $9: 25$. The mass numbers of the nuclei are in the ratio

The Avogadro number is $6 \times 10^{23}$. What will be the number of protons,neutrons,and electrons in $14 \, g$ of $_6C^{14}$?

If the radius of a nucleus with mass number $125$ is $1.5 \text{ fermi}$, then the radius of a nucleus with mass number $64$ is: (in $\text{ fermi}$)

The graph of $\ln \left(\frac{R}{R_0}\right)$ versus $\ln A$ is,where $R$ is the radius of a nucleus,$A$ is its mass number,and $R_0$ is a constant.

The radius $R$ of a nucleus of mass number $A$ can be estimated by the formula $R = (1.3 \times 10^{-15}) A^{1/3} \; m$. It follows that the mass density of a nucleus is of the order of $(M_{\text{prot}} \cong M_{\text{neut}} = 1.67 \times 10^{-27} \; kg)$.

According to the quark model,it is possible to build all the hadrons using