The sum of the first and third term of an ari | vedclass

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(C) Let the first three terms of the arithmetic progression be $(a - d)$,$a$,and $(a + d)$.According to the problem,the sum of the first and third ter

Vedclass · Accepted Answer

$4$

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(C) Let the first three terms of the arithmetic progression be $(a - d)$,$a$,and $(a + d)$.According to the problem,the sum of the first and third term is $12$:$(a - d) + (a + d) = 12$$2a = 12$$a = 6$Now,the product of the first and second term is $24$:$(a - d) 	imes a = 24$Substitute $a = 6$ into the equation:$(6 - d) 	imes 6 = 24$$6 - d = 4$$d = 2$The first term is $(a - d) = 6 - 2 = 4$.

The sum of the first and third term of an arithmetic progression is $12$ and the product of the first and second term is $24$. Find the first term.

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