The sum of the ages of 4 members of a family, | vedclass

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(A) Let the sum of the ages of the $4$ members $5$ $years$ ago be $94$ $years$.Since there are $4$ members,the total increase in their ages over $5$ $

Vedclass · Accepted Answer

$22$

Vedclass · Answer

(A) Let the sum of the ages of the $4$ members $5$ $years$ ago be $94$ $years$.Since there are $4$ members,the total increase in their ages over $5$ $years$ is $4 	imes 5 = 20$ $years$.Therefore,the sum of their present ages is $94 + 20 = 114$ $years$.Now,the daughter is replaced by a daughter-in-law,and the new sum of their ages is $92$ $years$.Let the age of the daughter be $D$ and the age of the daughter-in-law be $L$.The sum of the ages of the other $3$ members remains the same.So,$(Sum 	ext{ of } 3 	ext{ members}) + D = 114$ and $(Sum 	ext{ of } 3 	ext{ members}) + L = 92$.Subtracting the two equations: $D - L = 114 - 92 = 22$ $years$.Thus,the difference between the age of the daughter and that of the daughter-in-law is $22$ $years$.

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