The sum of oxidation states of two silver ion | vedclass

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Question

(C) The given complex is $[Ag(NH_{3})_{2}][Ag(CN)_{2}]$.This is a coordination compound consisting of a cationic part $[Ag(NH_{3})_{2}]^+$ and an anio

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) The given complex is $[Ag(NH_{3})_{2}][Ag(CN)_{2}]$.This is a coordination compound consisting of a cationic part $[Ag(NH_{3})_{2}]^+$ and an anionic part $[Ag(CN)_{2}]^-$.In the cationic part $[Ag(NH_{3})_{2}]^+$,let the oxidation state of $Ag$ be $x$. Since $NH_{3}$ is a neutral ligand,$x + 2(0) = +1$,so $x = +1$.In the anionic part $[Ag(CN)_{2}]^-$,let the oxidation state of $Ag$ be $y$. Since $CN^-$ has a charge of $-1$,$y + 2(-1) = -1$,so $y - 2 = -1$,which gives $y = +1$.The sum of the oxidation states of the two silver ions is $x + y = +1 + 1 = 2$.

The sum of oxidation states of two silver ions in $[Ag(NH_{3})_{2}][Ag(CN)_{2}]$ complex is $....$ .

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