The sum of the first $45$ natural numbers is:

$24-[2.4-\{0.24 \times 2-(0.024-?)\}]=22.0584$

Two numbers are such that their difference,their sum,and their product are in the ratio of $1: 7: 24$. The product of the numbers is:

$9999 + 8888 + 777 + ? = 19700$

$A$ number consists of two digits such that the digit in the ten's place is less by $2$ than the digit in the unit's place. Three times the number added to $\frac{6}{7}$ times the number obtained by reversing the digits equals $108$. The sum of the digits in the number is:

$A$ number is of two digits. The position of digits is interchanged and the new number is added to the original number. The resultant number will always be divisible by