The sum of $IE_1 + IE_2$ and $IE_3 + IE_4$ for elements $P$ and $Q$ are given below:
Element $IE_1 + IE_2$ $(kJ/mol)$ $IE_3 + IE_4$ $(kJ/mol)$
$P$ $2.45$ $8.82$
$Q$ $2.85$ $6.11$

Then,according to the given information,the incorrect statement$(s)$ is/are:

  • A
    $P^{2+}$ is more stable than $Q^{2+}$
  • B
    $P^{4+}$ is more stable than $Q^{4+}$
  • C
    $P^{4+}$ is less stable than $Q^{4+}$
  • D
    Both $(A)$ and $(C)$

Explore More

Similar Questions

From the ground state electronic configuration of the elements given below,pick up the one with the highest value of second ionization energy.

Which element has the maximum first ionization potential?

What may be the first ionisation energy of $Na$ if it has an effective nuclear charge of $1.84$,assuming the Bohr model of the $H$-atom is effective on it? (in $eV$)

The correct order in which the first ionisation potential increases is

Amongst the following elements with their electronic configurations given below,which one has the highest ionization energy?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo