The students in three classes are in the rati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the original number of students in the three classes be $4x$,$6x$,and $9x$ respectively.According to the problem,when $12$ students are added

Vedclass · Accepted Answer

$76$

Vedclass · Answer

(B) Let the original number of students in the three classes be $4x$,$6x$,and $9x$ respectively.According to the problem,when $12$ students are added to each class,the new ratio becomes $7:9:12$.We can set up the equation using the first two classes: $\frac{4x + 12}{6x + 12} = \frac{7}{9}$.Cross-multiplying gives: $9(4x + 12) = 7(6x + 12)$.$36x + 108 = 42x + 84$.Rearranging the terms: $108 - 84 = 42x - 36x$.$24 = 6x$,which gives $x = 4$.The total number of students before the increase is $4x + 6x + 9x = 19x$.Substituting $x = 4$,we get $19 	imes 4 = 76$.

The students in three classes are in the ratio $4:6:9$. If $12$ students are increased in each class,the ratio changes to $7:9:12$. Then the total number of students in the three classes before the increase is

Similar Questions

In a family,the ratio of expenses to savings is $5:3$. If the expenses increase by $60\%$ and the income increases by $25\%$,the savings decrease by $Rs. 3500$. Find the increased income (in $Rs.$) of the family.

If $B: A = 2: 3$ and $A: C = 5: 7$,then what is $(A + B) : (B + C)$?

The number of students in three classes are in the ratio $2:3:4$. If $12$ students are increased in each class,this ratio changes to $8:11:14$. The total number of students in the three classes in the beginning was:

$A$ box of sweets was distributed between $A$ and $B$ in the ratio $3:4$. If $A$ got $36$ sweets,what was the total number of sweets?

The ratio of the ages of Ram and Rahim $10 \text{ yr}$ ago was $1:3$. The ratio of their ages $5 \text{ yr}$ hence will be $2:3$. Then,the ratio of their present ages is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module