The structure of B_3N_3H_6 (borazine) is as f | vedclass

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(C) Borazine $(B_3N_3H_6)$ has a cyclic structure similar to benzene. In borazine,there are two types of hydrogen atoms: those attached to Boron $(B)$

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$4$

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(C) Borazine $(B_3N_3H_6)$ has a cyclic structure similar to benzene. In borazine,there are two types of hydrogen atoms: those attached to Boron $(B)$ and those attached to Nitrogen $(N)$. When replacing two hydrogen atoms with $X$ to form $B_3N_3H_4X_2$,we can have the following isomers: $1$. Both $X$ atoms on adjacent atoms (ortho-like): $B-N$ or $N-B$. $2$. Both $X$ atoms on alternate atoms (meta-like): $B-B$ or $N-N$. $3$. Both $X$ atoms on opposite atoms (para-like): $B-B$ or $N-N$. Specifically,the possible derivatives are: $(i)$ $1,2-X_2B_3N_3H_4$ (ortho) (ii) $1,3-X_2B_3N_3H_4$ (meta) (iii) $1,4-X_2B_3N_3H_4$ (para) (iv) $1,3-X_2B_3N_3H_4$ (another meta isomer) There are $4$ distinct derivative structures possible for $B_3N_3H_4X_2$.

The structure of $B_3N_3H_6$ (borazine) is as follows. How many derivative structures of $B_3N_3H_4X_2$ can be derived from the basic structure by the replacement of two hydrogen atoms?

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