The strength of a solution (S) in g/L is rela | vedclass

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(A) The strength $(S)$ of a solution in $g/L$ is defined as the mass of the solute in grams present in $1 \ L$ of the solution.Normality $(N)$ is defi

Vedclass · Accepted Answer

$S = N 	imes E$

Vedclass · Answer

(A) The strength $(S)$ of a solution in $g/L$ is defined as the mass of the solute in grams present in $1 \ L$ of the solution.Normality $(N)$ is defined as the number of gram equivalents of solute per liter of solution.$N = \frac{	ext{Number of gram equivalents}}{V 	ext{ (in } L)} = \frac{W / E}{V 	ext{ (in } L)}$Where $W$ is the mass of the solute in grams and $E$ is the equivalent weight.Rearranging the formula: $\frac{W}{V} = N 	imes E$Since $	ext{Strength } (S) = \frac{W}{V}$,we get $S = N 	imes E$.

The strength of a solution $(S)$ in $g/L$ is related to its normality $(N)$ and equivalent weight $(E)$ of the solute by the formula:

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