The strength of 50 volume solution of hydroge | vedclass

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(D) The decomposition of $H_2O_2$ is given by: $2H_2O_2 ightarrow 2H_2O + O_2$.At $STP$,$2 \ mol$ of $H_2O_2$ $(2 	imes 34 \ g = 68 \ g)$ produces

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(D) The decomposition of $H_2O_2$ is given by: $2H_2O_2 ightarrow 2H_2O + O_2$.At $STP$,$2 \ mol$ of $H_2O_2$ $(2 	imes 34 \ g = 68 \ g)$ produces $22.7 \ L$ of $O_2$.Strength of $V$ volume $H_2O_2$ solution is given by the formula: $	ext{Strength} (g/L) = \frac{V 	imes 34}{11.35}$.Given $V = 50$,so $	ext{Strength} = \frac{50 	imes 34}{11.35}$.$	ext{Strength} = \frac{1700}{11.35} \approx 149.77 \ g/L$.Rounding to the nearest integer,we get $150 \ g/L$.

The strength of $50$ volume solution of hydrogen peroxide is $...... \ g/L$ (Nearest integer). Given: Molar mass of $H_2O_2$ is $34 \ g \ mol^{-1}$. Molar volume of gas at $STP = 22.7 \ L$.

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