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(D) The reducing power of a metal is directly proportional to its standard oxidation potential $(E^{\circ}_{OP})$.Given standard reduction potentials

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$y > z > x$

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(D) The reducing power of a metal is directly proportional to its standard oxidation potential $(E^{\circ}_{OP})$.Given standard reduction potentials $(E^{\circ}_{RP})$:$E^{\circ}_{RP}(x) = 0.52 \ V$$E^{\circ}_{RP}(y) = -3.03 \ V$$E^{\circ}_{RP}(z) = -1.18 \ V$Since $E^{\circ}_{OP} = -E^{\circ}_{RP}$,the oxidation potentials are:$E^{\circ}_{OP}(x) = -0.52 \ V$$E^{\circ}_{OP}(y) = 3.03 \ V$$E^{\circ}_{OP}(z) = 1.18 \ V$Comparing the values,the order of oxidation potential is $y > z > x$.Therefore,the order of reducing power is $y > z > x$.

The standard reduction potential values of the three metallic cations $x, y, z$ are $0.52 \ V, -3.03 \ V$ and $-1.18 \ V$ respectively. The order of reducing power of their corresponding metals will be

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