The standard electrode potential (E^circ) for | vedclass

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(D) The standard electrode potential $(E^\circ)$ is an intensive property,meaning it does not depend on the amount of substance present or the stoichi

Vedclass · Accepted Answer

$+0.76 \ V$

Vedclass · Answer

(D) The standard electrode potential $(E^\circ)$ is an intensive property,meaning it does not depend on the amount of substance present or the stoichiometric coefficients of the reaction. For the reduction reaction: $Zn^{2+}_{(aq)} + 2e^- \rightarrow Zn_{(s)}$,$E^\circ = -0.76 \ V$. The given reaction is the reverse of the reduction reaction multiplied by a factor of $2$: $2Zn_{(s)} \rightarrow 2Zn^{2+}_{(aq)} + 4e^-$. Reversing the reaction changes the sign of the potential: $Zn_{(s)} \rightarrow Zn^{2+}_{(aq)} + 2e^-$,$E^\circ = -(-0.76 \ V) = +0.76 \ V$. Since the potential is an intensive property,multiplying the reaction by a coefficient does not change the value of $E^\circ$. Therefore,the standard potential for the reaction $2Zn_{(s)} \rightarrow 2Zn^{2+}_{(aq)} + 4e^-$ remains $+0.76 \ V$.

The standard electrode potential $(E^\circ)$ for the reaction $Zn^{2+}_{(aq)} + 2e^- \rightarrow Zn_{(s)}$ is $-0.76 \ V$. What is the standard electrode potential for the reaction $2Zn_{(s)} \rightarrow 2Zn^{2+}_{(aq)} + 4e^-$?

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