The stability of the following carbocations d | vedclass

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Question

(A) To determine the stability of carbocations,we analyze their aromaticity:$1$. $IV$ is the tropylium cation $(C_7H_7^+)$,which is aromatic ($6 \pi$

Vedclass · Accepted Answer

$IV > II > I > III$

Vedclass · Answer

(A) To determine the stability of carbocations,we analyze their aromaticity:$1$. $IV$ is the tropylium cation $(C_7H_7^+)$,which is aromatic ($6 \pi$ electrons,planar,cyclic,fully conjugated). It is highly stable.$2$. $II$ is the cyclopropenyl cation $(C_3H_3^+)$,which is aromatic ($2 \pi$ electrons,planar,cyclic,fully conjugated). It is also stable but less than $IV$ due to ring strain.$3$. $I$ is the cyclohexyl cation,which is non-aromatic. It is more stable than anti-aromatic systems.$4$. $III$ is the cyclopentadienyl cation,which is anti-aromatic ($4 \pi$ electrons,planar,cyclic,fully conjugated). It is the least stable.Thus,the order of stability is $IV > II > I > III$.

The stability of the following carbocations decreases in the order:

Similar Questions

Homolytic fission of the following alkanes forms free radicals: $CH_3-CH_3$,$CH_3-CH_2-CH_3$,$(CH_3)_2CH-CH_3$,and $CH_3-CH_2-CH(CH_3)_2$. The increasing order of stability of the resulting free radicals is:

The correct order of stability is:

Which of the following is the most stable cation?

The stability of the following carbocations follows the order:

What is the hybridization state of a carbocation?

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